x^2+4x+41=0

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Solution for x^2+4x+41=0 equation:


Simplifying
x2 + 4x + 41 = 0

Reorder the terms:
41 + 4x + x2 = 0

Solving
41 + 4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-41' to each side of the equation.
41 + 4x + -41 + x2 = 0 + -41

Reorder the terms:
41 + -41 + 4x + x2 = 0 + -41

Combine like terms: 41 + -41 = 0
0 + 4x + x2 = 0 + -41
4x + x2 = 0 + -41

Combine like terms: 0 + -41 = -41
4x + x2 = -41

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -41 + 4

Reorder the terms:
4 + 4x + x2 = -41 + 4

Combine like terms: -41 + 4 = -37
4 + 4x + x2 = -37

Factor a perfect square on the left side:
(x + 2)(x + 2) = -37

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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